Math 260, Spring 2012

From cartan.math.umb.edu

Math 260 --- Linear Algebra I

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(It isn't as hard as the documentation might make it seem. To see how to typeset the sentence "Consider a linear transformation \(T:R^2\rightarrow R^2\)," click the "edit" link at the top of this page and read the source code that generated it.)

Steven Glenn Jackson 02:42, 1 March 2012 (UTC)

Important Dates

  • 02/28/2012 - Exam 1
  • 04/17/2012 - Exam 2

Questions

  • If the kernel of a linear transformation is nontrivial, does that imply that the transformation is not injective and therefore the transformation matrix is not invertible? Patrickmclaren 02:11, 6 March 2012 (GMT)
Yes. If the kernel of \(T\) is non-trivial, then we have some non-zero \(\vec{v}\) with \(T(\vec{v})=\vec{0}\). But also \(T(\vec{0})=\vec{0}\), so \(T\) is not one-to-one and hence not invertible. Steven Glenn Jackson 15:27, 6 March 2012 (GMT)

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