Math 260, Spring 2012

From cartan.math.umb.edu

Math 260 --- Linear Algebra I

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Steven Glenn Jackson 02:42, 1 March 2012 (UTC)

Important Dates[edit]

  • 02/28/2012 - Exam 1
  • 04/17/2012 - Exam 2

Questions[edit]

  • If the kernel of a linear transformation is nontrivial, does that imply that the transformation is not injective and therefore the transformation matrix is not invertible? Patrickmclaren 02:11, 6 March 2012 (GMT)
Yes. If the kernel of \(T\) is non-trivial, then we have some non-zero \(\vec{v}\) with \(T(\vec{v})=\vec{0}\). But also \(T(\vec{0})=\vec{0}\), so \(T\) is not one-to-one and hence not invertible. Steven Glenn Jackson 15:27, 6 March 2012 (GMT)
  • If \(\varphi:\mathbb{R}^n\to\mathbb{R}^n\) is an isometry that fixes the origin\[\varphi(0) = 0\], then does \(\varphi\) preserve dot products? Patrickmclaren 02:12, 4 April 2012 (BST)
Yes. Since \(\phi\) is an isometry and fixes the origin, it is linear (this is the only part that's hard to prove). Then since it preserves distance and fixes the origin, it preserves length of vectors. So it is an orthogonal transformation according to the book's definition. The book gives a proof that such transformations preserve dot products. Steven Glenn Jackson 13:52, 4 April 2012 (BST)

Links[edit]