Math 361, Spring 2017, Assignment 9
From cartan.math.umb.edu
Carefully define the following terms, then give one example and one non-example of each:[edit]
- Vector space (over a field F).
- Subspace (of a vector space).
- Subspace generated (a.k.a. spanned) by a set S.
- Linear relation (in a set S).
- Linearly independent.
- Basis.
- dimFV (a.k.a. the dimension of V over F).
- [E:F] (a.k.a. the degree of E, regarded as an extension of F).
Carefully state the following theorems (you do not need to prove them):[edit]
- Theorem concerning the existence of bases.
- Theorem relating the cardinalities of two bases for the same vector space.
- Theorem relating bases to unique expansion of vectors as linear combinations.
- Dimension Formula.
- Corollary of the Dimension Formula analogous to Lagrange's Theorem in group theory.
- Corollary concerning subextensions of field extensions of prime degree.
- Theorem characterizing algebraic elements in terms of finite-dimensional subextensions.
- Theorem concerning sums, products, and inverses of algebraic elements.
Solve the following problems:[edit]
- Section 30, problems 1, 4, 5, 6, 7, and 8.
- Section 31, problems 1, 3, 5, 7, 22, 23, 24, 25, and 29.
Questions[edit]
The first homework question talks about bases for R2 no two of which have a vector in common. I am not sure where to start to find the three bases. Is the next several question ask a given basis for the indicated vector space over the field. Not sure where to start, with those questions. Where do I start to solve the problems?
- Any two vectors in R2, neither of which is a scalar multiple of the other, will form a basis for R2. So, for example, [11] and [12] will form a basis.
- Any simple algebraic extension has a "standard basis" {1,α,…,αd−1} where α is the generator and d is the degree of α over the base field. So, for example, Q(5√2) has Q-basis {1,5√2,(5√2)2,(5√2)3,(5√2)4}. -Steven.Jackson (talk) 10:28, 4 April 2017 (EDT)
I have a problem with question 22 section 31. The question is: Let (a+bi)∈C where a,b∈R and b≠0. Show that C=R(a+bi).(22 is not in the back of the book as an answer) Thanks again for the help.
- The simplest way to do this is to compute the dimension of R(a+bi), regarded as a vector space over R. It is a subextension of C, which has dimension two, so its dimension is either 1 or 2. In the first case, the subextension is trivial, contradicting the fact that b≠0 (hence a+bi∉R). So the dimension is two, and R(a+bi) is all of C. -Steven.Jackson (talk) 21:20, 9 April 2017 (EDT)