Math 361, Spring 2014, Assignment 3
Carefully define the following terms, then give one example and one non-example of each:[edit]
- Monic polynomial.
- Monic generator (of a principal ideal).
- Field extension.
- Extension field.
- Base field.
- Injection (associated with a field extension).
Carefully state the following theorems (you need not prove them):[edit]
- Classification of prime ideals in $F[x]$.
- Kronecker's Theorem.
Solve the following problems:[edit]
- Consider the polynomial $f = x^3 - 2$ in $\mathbb{Q}[x]$.
- Show that $f$ is irreducible over $\mathbb[Q]$.
- Now consider the extension field $E_1 = \mathbb{Q}[x]/\langle f\rangle$. Is $f$ still irreducible when regarded as a polynomial with coefficients in $E_1$? If not, then write an explicit non-trivial factorization of $f$ over $E_1$.
- Does $f$ split over $E_1$? (Warning: this is a hard question. In principle you can answer it now, with a lot of work, but soon we will learn an efficient way to answer it. If you prefer, take a guess at this and forge ahead.) If not, can you produce another extension $E_2$ over which it does split?
Questions:[edit]
Solutions:[edit]
Definitions:[edit]
- Monic Polynomial
A monic polynomial is a polynomial whose leading term is 1.
Example:
\(x^4 + 5x^2 + 7\)
Non-example:
\(5x^2\)
- Monic Generator of a Principal Ideal
Given an ideal \(\langle p \rangle\) of \(F[x]\), we can find a monic polynomial \(q\) such that \(\langle p \rangle = \langle q \rangle\).
Example:
The monic generator of the ideal \(\langle 5x^3 + 6x\rangle\) is \(x^3 + 6/5x\).
Non-example:
\(10x^3 + 12x\) is not a monic generator of the same ideal. Is it a generator, but it isn't monic.
- Field Extension
A field extension is a triple \((F,E,\iota)\) such that \(F\) and \(E\) are fields, and \(\iota:F\rightarrow E\) is a monomorphism.
Example:
\(\mathbb{Q},\mathbb{R},\iota\) is a field extension, where \(\iota(x)=x\).
Non-example:
\((\mathbb{Z},\mathbb{Q},\iota)\) is not a field extension, because \(\mathbb{Z}\) is not a field.
- Extension Field
Given a field extension \((F,E,\iota)\), \(E\) is the extension field.
Example:
In the above example, \(\mathbb{R}\) is the extension field.
Non-example:
\(\mathbb{Q}\) isn't.
- Base Field
Given a field extension \((F,E,\iota)\), \(F\) is the base field.
Example:
In the above example, \(\mathbb{Q}\) is the base field.
Non-example:
\(\mathbb{R}\) isn't.
- Injection of a Field Extension
\(\iota\).
Theorems:[edit]
- Classification of Prime Ideals in \(F[x]\)
An ideal of \(F[x]\) is prime if and only if it is generated by an irreducible polynomial. Remember that all ideals of \(F[x]\) are generated by a single element.
- Kronecker's Theorem
Given a polynomial \(p\) in \(F[x]\), we can find a field extension \(F,E,\iota\) such that \(p\) has a root in \(E\).
Solutions:[edit]
\(f\) is irreducible over \(\mathbb{Q}\) because it is a cubic with no roots.
So \(\alpha\) is a root of \(x^3-2\) over \(\mathbb{Q}/\langle f \rangle\). After all, \(\alpha^3 -2=0\) mod \(\langle f \rangle\). To actually factor the polynomial, we need to divide \(x^3-2\) by \(\alpha\) within the polynomial ring \(\mathbb{Q}/\langle f \rangle[x]\). The result is \(x^2+\alpha x + \alpha^2\). It's too hard to typeset the actual division, so I won't try. Just remember that \(\alpha^3=2\) in \(\mathbb{Q}/\langle f \rangle\).
This polynomial does not split over \(E_1\). \(x^3-2\) doesn't even split over \(\mathbb{R}\), and the field we've created is a "subset" of \(\mathbb{R}\).