Math 360, Fall 2021, Assignment 4

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Mathematicians are like Frenchmen: whatever you say to them they translate into their own language, and forthwith it is something entirely different.

- Goethe

Read:

  1. Section 4.

Carefully define the following terms, then give one example and one non-example of each:

  1. (Fun(S,S)).
  2. fg (the composition of the functions f and g).
  3. ι (the identity function from a set S to itself).
  4. Zn.
  5. +n (addition modulo n).
  6. n (multiplication modulo n).
  7. Semigroup.
  8. Monoid.
  9. Inverse (of an element of a monoid).
  10. Group.
  11. Abelian (group).

Carefully state the following theorems (you do not need to prove them):

  1. Theorem regarding associativity of composition.
  2. Theorem asserting that +n is well-defined.

Solve the following problems:

  1. Section 4, problems 1, 3, 5, 11, 12, 13, 14, 18, and 19.
  2. Give an example of (a) a binary structure which is not a semigroup, (b) a semigroup which is not a monoid, (c) a monoid which is not a group, and (d) a group which is not abelian.
  3. By making an operation table, determine which elements of the commutative monoid (Z5,5) have inverses. Then do the same for (Z6,6) and (Z8,8).
  4. Based on the results of the previous problem, try to make a conjecture regarding which elements of (Zn,n) have inverses.
  5. Carefully show that the operation n is well-defined (i.e. state and prove a theorem analogous to the theorem asserting that +n is well-defined).
--------------------End of assignment--------------------

Questions:

Solutions:

Theorems:

  1. +n is well-defined: if a=bmod(n) and c=dmod(n), then (a+c)=(b+d)mod(n).

Book Problems:

Other Problem :

  1. A binary structure which is not a semigroup: (Z,) , for a,bZ,ab=a+2(b+1);a semigroup which is not a monoid: (S,),S={a,b}, for all a,bS,ab=b; a monoid which is not a group: (Z3,), for a,bZ3,ab=(ab)mod3; a group which is not abelian: (S5,),S5={33 matrices whose determinant 0}, is matrix multiplication.
  2. Elements: (Z5,5):1,2,3,4;(Z6,6):1,5;(Z8,8):1,3,5,7.
  3. for n, for all aZ, if a is not 1 and a divides n, a and any abforanybZ will not have inverse
  4. For operation n