Math 360, Fall 2021, Assignment 4
From cartan.math.umb.edu
Mathematicians are like Frenchmen: whatever you say to them they translate into their own language, and forthwith it is something entirely different.
- - Goethe
Read:
- Section 4.
Carefully define the following terms, then give one example and one non-example of each:
- (Fun(S,S)).
- f∘g (the composition of the functions f and g).
- ι (the identity function from a set S to itself).
- Zn.
- +n (addition modulo n).
- ⋅n (multiplication modulo n).
- Semigroup.
- Monoid.
- Inverse (of an element of a monoid).
- Group.
- Abelian (group).
Carefully state the following theorems (you do not need to prove them):
- Theorem regarding associativity of composition.
- Theorem asserting that +n is well-defined.
Solve the following problems:
- Section 4, problems 1, 3, 5, 11, 12, 13, 14, 18, and 19.
- Give an example of (a) a binary structure which is not a semigroup, (b) a semigroup which is not a monoid, (c) a monoid which is not a group, and (d) a group which is not abelian.
- By making an operation table, determine which elements of the commutative monoid (Z5,⋅5) have inverses. Then do the same for (Z6,⋅6) and (Z8,⋅8).
- Based on the results of the previous problem, try to make a conjecture regarding which elements of (Zn,⋅n) have inverses.
- Carefully show that the operation ⋅n is well-defined (i.e. state and prove a theorem analogous to the theorem asserting that +n is well-defined).
Questions:
Solutions:
Theorems:
- +n is well-defined: if a=bmod(n) and c=dmod(n), then (a+c)=(b+d)mod(n).
Book Problems:
Other Problem :
- A binary structure which is not a semigroup: (Z,△) , for a,b∈Z,a△b=a+2(b+1);a semigroup which is not a monoid: (S,△),S={a,b}, for all a,b∈S,a△b=b; a monoid which is not a group: (Z3,∗), for a,b∈Z3,a∗b=(a⋅b)mod3; a group which is not abelian: (S5,∗),S5={3∗3 matrices whose determinant ≠0}, ∗ is matrix multiplication.
- Elements: (Z5,⋅5):1,2,3,4;(Z6,⋅6):1,5;(Z8,⋅8):1,3,5,7.
- for n, for all a∈Z, if a is not 1 and a divides n, a and any a∗bforanyb∈Z will not have inverse
- For operation ⋅n