Math 361, Spring 2017, Assignment 11

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Revision as of 18:51, 15 April 2017 by Anamaria.Ronayne (talk | contribs) (Questions)

Carefully define the following terms, then give one example and one non-example of each:

  1. Compass-and-straightedge construction.
  2. Constructible number.

Carefully state the following theorems (you do not need to prove them):

  1. Theorem concerning sums, differences, products, and inverses of constructible numbers.
  2. Theorem concerning square roots of constructible numbers.
  3. Theorem concerning the degrees of constructible numbers over $\mathbb{Q}$.
  4. Theorem concerning duplication of the cube.
  5. Theorem concerning squaring the circle.

Describe the following compass-and-straightedge constructions:

  1. Perpendicular bisector.
  2. Dropping a perpendicular.
  3. Constructing a parallel.
  4. Multiplication of lengths.
  5. Inversion of length.
  6. Square root of length.

Solve the following problems:

  1. Determine whether the following numbers are constructible:
(a) $\frac{\sqrt{5}-1}{4}$.
(b) $\sqrt[6]{7}$.
(c) $\alpha$ where $\alpha$ is a root of the polynomial $x^3+3x-12$. (Hint: use Eisenstein's criterion.)
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Questions

A) $\frac{\sqrt(5) - 1}{4}$

$\alpha = \frac{\sqrt(5) - 1}{4}$

$4\alpha = \sqrt(5) - 1$

$4\alpha +1 = \sqrt(5)$

$(4\alpha +1)^2 = \sqrt(5)^2$

$ 16\alpha^2 + 8\alpha + 1= 5$

$ 16\alpha^2 + 8\alpha + 4= 0$

Therefore because the problem is of degree two it is constructible. Is my reasoning totally off?

The Eisenstein's criterion: Can be applied like this:

$8x^3+6x^2-9x+24$ where $p=3$ because $3^2=9$ and does not go into 24 evenly therefore the equation is irreducibility.

C)$x^3+3x-12$ where $p=3$ because $3^2=9$ and does not go into 12 evenly therefore the equation is irreducibility. How does this help us determine weather the following is constructible or not?

Solutions