Math 440, Fall 2014, Assignment 1
The beginner ... should not be discouraged if ... he finds that he does not have the prerequisites for reading the prerequisites.
- - P. Halmos
Carefully define the following terms, then give one example and one non-example of each:
- Cartesian product (of two sets).
- Power set (of a set).
- Equinumerous (sets).
- Countable set.
- Uncountable set.
- Cardinality of the continuum.
- Partial order.
- Maximal element (of a partially ordered set).
- Largest element (of a partially ordered set).
- Chain (in a partially ordered set).
Carefully state the following theorems (you need not prove them):
- Cantor-Bernstein Theorem.
- Cantor's Theorem.
- Continuum Hypothesis (of course this is not a theorem, though it is sometimes taken as an axiom).
- Axiom of Choice (see above).
- Zorn's Lemma.
Solve the following problems:
- Prove Cantor's Theorem (exercise 1I.1 contains many hints).
- Problems 1E and 1H (you will use the results of 1H incessantly for the rest of the semester).
Questions:
Solutions:
- Cartesian Product of Two Sets:
Let \(A\) and \(B\) be sets. The cartesian product of \(A\) and \(B\), \(A \times B\), is the set:$$ A \times B = \{(a,b)| a\in A , b \in B\} $$
Example:
The cartesian product of \(\{1,2\}\) and \(\{a,b\}\) is \(\{(1,a), (1,b), (2,a), (2,b)\}\)
Non-Example:
Remember that the Cartesian product is a set of tuples. Don't confuse it with the union of two sets, which would be \(\{1,2,a,b\}\) for the above example.
- Power Set of a Set:
Let \(A\) be a set. The power set of \(A\) is the set of all subsets of \(A\): $$ \mathscr{P}(A) = \{B | B \subseteq A\} $$
Example:
The power set of \(\{1,2\}\) is \(\{\emptyset,\{1\}, \{2\}, \{1,2\}\}\)
Non-Example:
- Equinumerous Sets:
Two sets \(A\) and \(B\) are equinumerous if there is a bijection between the two sets.
Example:
\(\mathbb{Z}\) and \(\mathbb{Q}\) are equinumerous.
Non-Example:
\(\mathbb{Z}\) and \(\mathbb{R}\) are not equinumerous.
- Countable Set:
A set \(S\) is countable if there is an injection from \(S\) to \(\mathbb{Z}\) (or any other countable set.)
Example:
\(\{a,b,c\}\) is countable - it can easily be injected to \(\mathbb{Z}\).Non-Example:
\(\mathbb{R}\)
- Uncountable Set:
A set is uncountable if there is no injection from it to \(\mathbb{Z}\).
Example:
\(\mathbb{R}\).
Non-Example:
- Cardinality of the Continuum:
The cardinality of the continuum, \(\mathbb{c}\), is the cardinality of the real numbers.
Example:
\(\mathbb{R}\).
Non-Example:
\(\mathbb{Z}\)
- Partial Order:
A partial ordering on a set \(A\) is a relation that is reflexive, transitive, and anti-symmetric. A set with a partial order is also called a poset.
Example:
\((\mathbb{R},\leq)\) is a partial ordering of the reals.
Non-Example:
\((\mathbb{R},\lt)\) is not a partial ordering - it is not reflexive.
- Maximal Element of a Poset:
If \((A,\leq)\) is a poset, then an element \(b \in A\) is maximal if there is no \(c \in A\) such that \(b \leq c\).
Example:
a is maximal in the alphabet, by alphabetical order.
Non-Example:
There is no maximal natural number.
- Largest Element of a Poset:
If \((A,\leq)\) is a poset, then an element \(b \in A\) is the largest element of \(A\) if for all \(c\in A\) \(b \geq c\).
Example:
3 is the largest element of the set \(\{1,2,3\}\).
Non-Example:
The set \((0,1)\) has no largest element (within itself).
- Chain in a Poset:
Given a poset \((A,\leq)\), a chain in \(A\) is a totally ordered subset \(B\). Meaning for every two elements \(a,b \in B\), either \((a,b) \in \leq\) or \((b,a) \in \leq\).
Example:
The integers are a chain in the real numbers with respect to \(\leq\).
Non-Example:
Theorems:
- Cantor-Bernstein Theorem
Let \(A\) and \(B\) be sets. If there are injections \(f:A \rightarrow B\) and \(g:B \rightarrow A\), then \(|A| = |B|\). (Does not require the axiom of choice).
- Cantor's Theorem
For all sets \(A\), \(\mathscr{P}(A)\) has strictly greater cardinality than \(A\).
- Continuum Hypothesis
There does not exist a set \(A\) such that \(|\mathbb{Z}| \lt |A| \lt \mathbb{c}\).
- Axiom of Choice
Let \(X\) be a set of sets. Then there exists a function \(f\) such that \(f(x) \in x\) for all \(x \in X\). Less formally, if we have a collection of sets, we have a way to choose one element from each of those sets.
- Zorn's Lemma
Let \(A\) be a poset. If every chain in \(A\) has a maximal element, then \(A\) has a maximal element.