Math 361, Spring 2014, Assignment 5
Carefully define the following terms, then give one example and one non-example of each:[edit]
- Vector space (over a field $F$).
- Spanning set.
- Linearly independent set.
- Basis.
- Dimension.
- Algebraic extension.
- Algebraically closed field.
- Algebraic closure.
Carefully state the following theorems:[edit]
- Theorem concerning the existence of bases.
- Dimension formula.
- Theorem relating finite-dimensional extensions to algebraic extensions.
- Theorem concerning the existence of algebraic closures.
Solve the following problems:[edit]
- Section 30, problems 1, 4, 5, 7, and 9.
- Section 31, problems 1, 3, 5, 23, and 24.
Questions:[edit]
Solutions:[edit]
Definitions:[edit]
- Vector space (over a field $F$).
Let $F$ be a field. A vector space over F is a triple $(V,+,\mu)$ where $(V,+)$ is an abelian group (with identity $\vec{0}$) and $\mu:F\times V\rightarrow V$ satisfies:
$$(c_1+c_2)\vec{v} = c_1\vec{v} +c_2\vec{v}$$ $$c(\vec{v_1}+\vec{v_2}) = c\vec{v_1} + c\vec{v_2}$$ $$ c_1(c_2\vec{v}) = (c_1c_2)\vec{v}$$ $$1\cdot\vec{v} = \vec{v}$$
Note: we abbreviate $\mu (c,\vec{v})$ by $c\vec{v}$
- Spanning set.
Let $S$ be any subset of the vector space $V$. $S$ spans $V$ if every element of $V$ is a linear combination.
- Linearly independent set.
$S$ is a linearly independent if no element of $S$ is a linear combination of other elements.
- Basis.
$S$ is a basis for $V$ is if it spans and is linearly independent.
- Dimension.
The dimension of $V$ over $F$ is the cardinality of any basis written $dim_F V$ or $\left[V:F\right]$
- Algebraic extension.
The extension $F\rightarrow E$ is algebraic is every element in $E$ is algebraic over $F$.
Example:
$\mathbb{C}$ is algebraic $/\mathbb{R}$
Non-example
$\mathbb{R}$ is not algebraic $/\mathbb{Q}$
- Algebraically closed field.
A field $F$ is algebraically closed if it satisfies any of the following:
- Every non-constant polynomial in $F\left[ x\right]$ has a root in $F$.
- Every non-constant polynomial in $F\left[ x\right]$ splits over $F$.
- Every irreducible polynomial in $F\left[ x\right]$ has degree 1.
- Every algebraic extension of $F$ is trivial.
Example:
$\mathbb{C}$ <\p>
Non-example:
$\mathbb{R}$ is not algebraically closed since $x^2+1$ is not constant but has no roots in $\mathbb{R}$.
- Algebraic closure.
An extension $F\rightarrow\Omega$ is said to be an algebraic closure of $F$ if:
- it is algebraic
- $\Omega$ is algebraically close
Example:
$\mathbb{R}\rightarrow\mathbb{C}$ is an algebraic closure of $\mathbb{R}$.
Non-example
$\mathbb{Q}\rightarrow\mathbb{C}$ is not an algebraic closure of $\mathbb{Q}$, since it is not an algebraic extension.
Theorems:[edit]
- Theorem concerning the existence of bases.
Every vector space has a basis
or
Any linearly independent set can be grown to a basis and any spanning set can be shrunk to a basis.
- Dimension formula.
Suppose we have a chain of extensions
$$F\rightarrow K\rightarrow E$$
Then $\left[E:F\right] = \left[E:K\right]\left[K:F\right]$.
- Theorem relating finite-dimensional extensions to algebraic extensions.
The extension $F\rightarrow E$ is a finite extension $\Leftrightarrow$ it is algebraic and finitely generated.
- Theorem concerning the existence of algebraic closures.
- Every field has an algebraic extension
- Universal mapping property of an algebraic closure: If $F\rightarrow \bar{F}$ is an algebraic closure, and $F\rightarrow E$ is any algebraic extension, then there exists a monomorphism $E\rightarrow\bar{F}$.
- If $\Omega$ is any algebraically closed extension of $F$, then there exists a unique $\phi:\bar{F}\rightarrow\Omega$