Math 361, Spring 2014, Assignment 4

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Revision as of 14:09, 1 March 2014 by Evan.Blanch (talk | contribs) (Solutions:)

Carefully define the following terms, then give one example and one non-example of each:

  1. Algebraic element (of an extension field).
  2. Minimal polynomial (of an algebraic element).
  3. Conjugate (of an algebraic element).
  4. Subextension generated by a subset.
  5. Finitely generated extension.
  6. Simple extension.

Carefully state the following theorems (you need not prove them):

  1. Classification of simple extensions.

Solve the following problems:

  1. Section 29, problems 1, 5, 7, 11, and 13.
--------------------End of assignment--------------------

Questions:

1. Is the quiz still going to be on Monday now that you posted the homework so late?

No, there will be no quiz this Monday. --Steven.Jackson (talk) 21:22, 22 February 2014 (EST)

2. Is there a quiz tomorrow or this week?

No, the next quiz is Monday, March 10. --Steven.Jackson (talk) 22:00, 27 February 2014 (EST)

Solutions:

  1. Algebraic element (of an extension field).

    Suppose $F\rightarrow E$ is an extension and $\alpha\in E$. We say that $\alpha$ is algebraic over $F$, if there is a non-constant $p\in F[x]$ such that $p\left(\alpha\right)=0$.

    Example:

    In $\mathbb{Q}\rightarrow\mathbb{C}$, $i$ is algebraic /$\mathbb{Q}$ because it is a root of $x^2+1$</p><p>'''Non-Example:'''</p><p>In $\mathbb{Q}\rightarrow\mathbb{C}$, $\pi$ is not algebraic, or transcendental / $\mathbb{Q}$ </p><br><p>''Note:'' In $\mathbb{R}\rightarrow\mathbb{C}$, $\pi$ is algebraic /$\mathbb{R}$ it is a root of x-$\pi$.</p><br><br> # Minimal polynomial (of an algebraic element).<p>For $\alpha\in E$, set the ''annhilator'', $ann_{F[x]}(\alpha)=\{f\in F[x]|f(\alpha)=0\}$. This is an ideal of $F[x]$.</p><p>$ann_{F[x]}(\alpha)=0\Leftrightarrow\alpha$is transcendental over $F$</p><p>Otherwise,(if $\alpha$ is algebraic over $F$) $ann(\alpha)$ has a unique monic generator, $irr(\alpha , F)$, which is called the minimal polynomial.</p><p>'''Example:'''</p><p>In $\mathbb{R}\rightarrow\mathbb{C}$, $irr(i,\mathbb{R}) = x^2+1$.</p><p>To determine the minimal polynomial, $irr(1+i,\mathbb{R})$,</p><p>Set $\alpha= 1+i$, then '"`UNIQ-MathJax2-QINU`"' '"`UNIQ-MathJax3-QINU`"' '"`UNIQ-MathJax4-QINU`"' '"`UNIQ-MathJax5-QINU`"' So $irr(1+i,\mathbb{R})=x^2-2x+2$.</p><p>'''Non-Example:'''</p> # Conjugate (of an algebraic element).<p>If $\alpha ,\beta\in E$ and are algebraic $/F$ we write $\alpha\sim_F\beta$ (read "$\alpha$ is conjugate to $\beta$") if and only if '"`UNIQ-MathJax6-QINU`"'.</p><p>'''Example:'''</p><p>In $\mathbb{Q}\rightarrow\mathbb{R}$, $\sqrt{2}\sim_\mathbb{Q}-\sqrt{2}$, since: '"`UNIQ-MathJax7-QINU`"' '"`UNIQ-MathJax8-QINU`"'</p><p>'''Non-example:'''</p><p>In $\mathbb{R}\rightarrow\mathbb{R}$, $\sqrt{2}\nsim_\mathbb{R}-\sqrt{2}$, since: $$irr(\sqrt{2},\mathbb{Q}) = x-\sqrt{2}$$ $$irr(-\sqrt{2},\mathbb{Q}) = x+\sqrt{2}$$

  2. Subextension generated by a subset.
  3. Finitely generated extension.
  4. Simple extension.